Flowchart, algorithm C code for various program .

 1.  WAP to calculate the Factorial of a given number N in Flowchart, algorithm and C .

Algorithm:

Step 1: Start

Step 2: Declare Variable n, f, i

Step 3: Read number n from User

Step 4: Initialize Variable f=1 and i=1

Step 5: Repeat Until i<=number

Step 6: f=f*i

Step 7: i=i+1

Step 8: Print f

Step 9: Stop

Flow Chart:

Code :

#include<stdio.h>

int main(){

int i,f=1,num;

printf(“Enter a number: “);

scanf(“%d”,&num);

for(i=1;i<=num;i++)

f=f*i;

printf(“Factorial of %d is: %d”,num,f);

return 0;

}

Output:

Enter a number: 10

Factorial of 10 is: 3628800

2. WAP to calculate the given number is Positive of Negative in Flowchart, algorithm and C .

Algorithm:

Step 1:  Start

Step 2: Read a number n from user

Step3: If n is less than zero

Step4: Print The number is Negative number

Step5: Else if the number is greater than zero

Step6: Print The number is Positive number

Step7: Else Print the number is zero

Step8: End

Flow Chart:

Code :

#include <stdio.h>

int main(){

 int num;

printf(“Input a number :”);

 scanf(“%d”, &num);

 if (num >= 0)

 printf(“%d is a positive number \n”, num);

 else

 printf(“%d is a negative number \n”, num);

return 0;

}

Output:

Input a number :4

4 is a positive number

3. WAP to find whether the input number is odd or Even in Flowchart, algorithm and C .

Algorithm:

Step 1: Start

Step 2: Read Number n

Step 3: If n mod 2 = 0 Then

Step4: Print  n is an Even Number.

Step5:  Else Print n is an Odd Number.

Step 6: Stop

Flowchart :

Code :

#include <stdio.h>

int main()

{

int num1, rem1;

printf(“Input an integer : “);

scanf(“%d”, &num1);

rem1 = num1 % 2;

if (rem1 == 0)

printf(“%d is an even integer\n”, num1);

else

printf(“%d is an odd integer\n”, num1);

return 0;

}

Output:

Input an integer : 4

4 is an even integer

4. WAP  to  take  information  of  a  student  as  input  and  display  them  suitably.  Information includes name, roll no, age, phone number and email address in Flowchart, algorithm and C .

Algorithm:

Step 1: Start

Step 2: Declare variable name,roll no,age,phone number and email .

Step 3: Read name,rollno,age,phone number and email .

Step4: Print name,rollno,age,phone number and email .

Step5: Stop

Flow Chart :  

Code :

#include <stdio.h>

#include <conio.h>

int main(){

char nam[20];

int roll;

char adress[25];

int age;

int phon;

printf(“Enter The name “);

gets(nam);

printf(“Enter The Adress “);

gets(adress);

printf(“Enter the roll no”);

scanf(“%d”, &roll);

printf(“Enter the age”);

scanf(“%d”, &age);

printf(“Enter the Phone  no”);

scanf(“%d”, &phon);

printf(“The name is %s\n”, nam);

printf(“The Adress %s\n”, adress);

printf(“The Roll no is %d\n”, roll);

printf(“The age is %d\n”, age);

printf(“The Phone number is %d\n”, phon);

return 0;

}

Output:

Enter The name kiran

Enter The Adress butwal

Enter the roll no20

Enter the age18

Enter the Phone  no984855

The name is kiran

The Adress butwal

The Roll no is 20

The age is 18

The Phone number is 984855

4. WAP to swap two numbers input by uers in Flowchart, algorithm and C .

Algorithm :

Step1: Start

Step2: Declare a variable a,b and c as integer

Step3: Read two numbers a and b

Step4: c=a

Step5: a=b

Step6: b=c

Step7: Print a and b

Step9: End

Flowchart :

Code:

#include <stdio.h>

int main()

{

int a;

int b;

int c;

printf(“Input enter 1st Number”);

scanf(“%d”, &a);

printf(“Input Enter 2nd Number”);

scanf(“%d”, &b);

c = a;

a = b;

b = c;

printf(“The 1st number is %d\n”, a);

printf(“The 2ndst number is %d”, b);

return 0;

}

Output :

Input enter 1st Number5

Input Enter 2nd Number6

The 1st number is 6

The 2ndst number is 5

5. WAP to calculate compound amount when p n and r are given in Flowchart, algorithm and C  .

Algorithm:

Step1: Start

Step2: Declare a variable p,n and r and amount as integer

Step3: Read p,n and r

Step4: amount =p*[(1+r/n)^nt]

Step5: Print amount

Step6: End

Flowchart :

Code :

#include<stdio.h>

#include <math.h>

int main(){

float p,r,n,t,amount;

printf(“Enter principal”);

scanf(“%f”,&p);

printf(“Enter Rate”);

scanf(“%f”,&r);

printf(“Enter number of times interest”);

scanf(“%f”,&n);

printf(“Enter time”);

scanf(“%f”,&t);

amount = p* (pow((1 + r / n), t*n));

printf(“The Compount interest amount is %f”,amount);

return 0;

}

           Output:

Enter principal4500

Enter Rate2

Enter number of times interest1

Enter time2

The Compount interest amount is 40500.000000